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This historic book may have numerous typos and missing text. Purchasers can usually download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1839 edition. Excerpt: ...Stroke 4 feet, or 216 feet velocity per minute, Weight on each circular inch of the safety valve 1 lbs. or 11.78 4-2.5 = 14.28 lbs. atmospheric pressure included. Steam cut off from the cylinder when the piston has moved frds of the stroke, or 32 inches. Resistance and friction 10 lbs. per square inch, or 7.85 lbs. per circular inch; required the useful effect of the engine in horses' power. 48 1 4 28--= 1.5, and--: = 9.52. The hyperbolic 32 l.o logarithm of 1.5 4-1 = 1.40546 X 9.52 = 13.37 lbs. per circular inch of uniform elastic force, and 13.37--7.85 = 5.52 lbs. effective force; hence, 202 X 5.52X216 476928 AA = = 14.4 horses power. 33000 33000 t Example 2.--Required the diameter of the cylinder for a condensing engine of 14.4 horses' power, and also the weight on each circular inch of the safety valve, in order to produce steam of 13.37 lbs. uniform elastic force, the steam to be cut off from the cylinder when the piston has moved 32 inches of its stroke--velocity of the piston 216 feet per minute--resistance and friction 7.85 lbs. per circular inch; 13.37--7.85 = 5.52 lbs. effective power of the steam per circular inch; hence, 33000_x 14.4 475200. =--= 400 = 20 m. dla. 216 X 5.52 1192 v 48 Again, 4 feet = 48 inches, and--= 1.5; the hyper bolic logarithm of 1.5 plus 1 = 1.4054; hence, 13.37 X 1.5 1.4054 = 14.28 lbs. total force of steam in the boiler per circular inch; and 14.28--11.78, or the pressure of the atmosphere = 2.5 lbs. effective elastic force or weight upon each circular inch of the safety valve. Example 3.--What is the power of a non-condensing engine, having a cylinder of 9 inches diameter, a stroke of 2 feet, or 200 feet velocity per minute, and a pressure of steam in the boiler of 40 lbs. per square inch, ...
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